Thread: multiply int..

How do I write the code for:

int a, b;

b = a^4 ; /* that doesn't work */

b = a * a * a; have I done so far...

Is there a right way

thank you all.

here my code should help you...

#include <math.h>
#include <stdio.h>


int main()

{
int x, y, i ;
char yes;
char var;
int result = 1 ;

again:

printf("Please enter your calculation in this format: 6*5..\n\n");
scanf("%d%c%d",&x,&var,&y);


switch(var)
{

case '+':

printf("answer = %d\n",x+y);

break;

case '-':

printf("answer = %d\n",x-y);

break;


case '*':

printf("answer = %d\n",x*y);

break;


case '/':

printf("answer = %d\n",x/y);

break;


case '^':


{

for(i=0; i<y; i++)

result *=x;

printf("answer = %d\n\n",result);

break;


default:

printf("Wrong syntax please try again\n");
}

}
}

>b = a^4 ; /* that doesn't work */

Well, that depends on what you want to do. The ^-operator is the XOR operation.

>b = a * a * a; have I done so far...

So you want to work with powers? You could use the following pseudocode.

Code:

pwr = 1;
for i = 1 to n
    pwr = pwr * a;

there's the pow function in <math.h>

there's the pow function in <math.h>

True. However it is slower than doing a*a*a*a.