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float type- beginner Q

This is a discussion on float type- beginner Q within the C Programming forums, part of the General Programming Boards category; hi, what is wrong with this code : Code: #include <stdio.h> #include <stdlib.h> int main(){ int a =1; int b ...

  1. #1
    Registered User
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    float type- beginner Q

    hi,

    what is wrong with this code :

    Code:
    #include <stdio.h>
    #include <stdlib.h>
    
    int main(){
    int a =1;
    int b = 2;
    int c = 0;
    float i = 0;
    
    c= a-b;
    i = a/b;
    printf("%d,%f\n",c,i);
    }
    I am expecting to print 2 numbers : -1 and 0.5, but i get -1 and 0.000000. What am i doing wrong

    thank you

    baxy

  2. #2
    SAMARAS std10093's Avatar
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    Code:
    i = (float)a/(float)b;
    What happens is that the division kills your precision
    dennis.cpp and baxy like this.

  3. #3
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    When you do a/b where both 'a' and 'b' are ints, the compiler uses integer arithmetic and returns an int result. If you want to ensure the division is done using floating point, force one of the numbers to be float: i = (float)a / b
    dennis.cpp and baxy like this.

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