Thread: Simle macro

Hi All;

Looking for hepl with a simple macro or even is it possible. I can do macro functions but this is annoying me.

Basically i have a #define called START. I want start to have two values, lets say 4 and 8.

Then i want to check if the input value is equal to start.

Would of thought this would work:
#define START(x) ((x) == 4 ? (x) == 8)

Thanks

Actually got it there now, what i have is:
#define START(x) (x) == 4| (x) == 8

If any better way let us know
Thanks

ALWAYS parenthesize all arguments and the whole macro expression

Code:

#define START(x) ((x) == 4 | (x) == 8)

This is binary OR; I think you need logical OR (though the result is the same for this expression)

Code:

#define START(x) ((x) == 4 || (x) == 8)

But I suggest a different alternative: make it a function rather than a macro

Code:

int isStart(int x) { return (x == 4 || x == 8); }