Returning a string

I need to reverse a string and display the original using one function. I have the function to reverse it, but i dont know how to display the original one. Any help would be appreciated.

Code i have so far:

Code:

#include <string.h>
#include <stdio.h>
#define CAPACITY 35


void reverseString(char *str)
int main (void)
{
    char first[CAPACITY];
    char last[CAPACITY];
    printf(" Enter your first and last name: ");
    scanf("%s %s", first, last);
    reverseString(first, first);
    reverseString(last, last);
    printf("The reverse of your name is: %s,%s \n", first, last);
}


void reverseString(char *str)
{
    char *p = str;
    char *q = str + strlen(str) - 1;
    char temp;
    
    while(p<q)
    {
        temp = *p;
        *p = *q;
        *q = temp;
        ++p;
        --q;
    }    
}

Your function works by overwriting the original string, so before calling your function you can either:
1) print the original string
2) make a copy of the original string to print later (see strcpy() in strings.h)

Code:

#include <ctype.h>
#include <stdio.h>
#include <string.h>

static char *rev(char *to, const char *from)
{
    const char *endp = from + strlen(from);
    char *save = to;

    while (endp > from)
        *to++ = *--endp;
    *to = '\0';
    return save;
}

static int read(char *to, size_t n)
{
    int c;

    n--;
    while ((c = getchar()) != EOF && !isspace(c))
        if (n) {
            *to++ = c;
            n--;
        }
    *to = '\0';
    return c;
}

int main(void)
{
    char first[35], last[35];
    char rfirst[sizeof first], rlast[sizeof last];

    while (read(first, sizeof first) != EOF
     && read(last, sizeof last) != EOF)
        printf("%s %s\n", rev(rfirst, first), rev(rlast, last));
    return 0;
}