Thread: Array manipulation doesn't work in printf

I have this void function that modifies an array count[]. When I call this function inside printf, and print the resulting count[0] in the same printf, why isn't the array modified?

Code:

#include<stdio.h>


int test(int n, int count[])
{
    count[0]++;
    return 8;
}


int main()
{
    int count[5] = {0};
    printf("%d %d", test(5,count), count[0]);
    return 0;
}

The output is 8 0 instead of 8 1.

printf, like any function, is free to evaluate its' arguments in any order.

I see. Thanks!