Thread: Need help debugging code - Program uses function to sort array

I have been working on this all day and cant seem to work anything out.The program accepts the array values and stops. No compiler errors.

Any help whatsoever is greatly appreciated!

Code:

#include <stdio.h>
#include <stdlib.h>
int *ptr;
int* sort(int numbers[], int size);
int main(int argc, char *argv[])
{
  //declaring variables//
  int x;
  int i;
  int counter;
  int place1;
  int place2;
  int place3;
  int place4;
  int p;
  int size;
  
  //Prompts for and accepts integers//
  printf("How many integers in array?\n");
  scanf(" %d", &size);
  int numbers[size];
  
  for(i=0;i<(size);i++)
  {
  printf("Enter Number #%d  ", i+1);
  scanf(" %d", &numbers[i]);
  }
 
  //sorts array//
  ptr = sort(numbers,size);
  
  //prints sorted array//
  for(p=0;p<size;p++)
  {
  printf(" %d", *(ptr+p));
  }     
  
  system("PAUSE");    
  return 0;
}




int* sort(int numbers[], int size)
{
 //declaring variables//
 int x;
 int smallest;
 int holdsvar;
 int y;
 //sorts array by finding min value//
 for(x=0; x=(size-1) ; x++)
 {
          smallest=x;
          for(y=x; y=(size-1); y++)  
          {
                   if (numbers[y] < numbers[smallest])
                   {
                                  smallest=y;
                   }
          }
 //switches analysed spot(0->array size) with smallest value//
 holdsvar=numbers[x];
 numbers[x]=numbers[smallest];
 numbers[smallest]=holdsvar;
 }         
         
return &numbers[0];
}

Originally Posted by Adak

Your compiler allows array declarations from local variables?

I'm impressed!

Yeah, it's a feature added in C99. But I think you use a pre-1999 compiler which doesn't have that feature.

Thank you stahta01.


I was assigning (size-1) to x...ooops

To resolve this i changed

Code:

for(x=0; x=(size-1) ; x++)

to

Code:

for(x=0; x<size ; x++)

for both "for" loops in the sort function.
Program works now, thanks guys!