Thread: Simulate the malloc function using a static array

Hello

It has been a long time since I used C. So therefore I'm trying to refresh my knowledge by simulating the malloc function. I want to use a static array and I want to "malloc" memory from this array.

This is the code I got so far:

Code:

char memory[10];

void initMemory(){
	
	int i=0;
	for(i=0; i < 10; i++){
		memory[i] = '?';
	}
}

void* malloc_t(int size){

	int i=0;
	int crtSize = 0;
	for(i=0; i < 10; i++){
		if(memory[i] == '?'){
			if(crtSize == size){
				return &memory[i-size];
			}
			crtSize++;
			
		}else{
			crtSize = 0;
		}
	}
}

int main(void){

	initMemory();
	char *string = (char*)malloc_t(5 * sizeof(char));
	//strcpy(string,"test\0");
	string = "test";
	printf("string: %s\n", string);
	
	int i=0;
	for(; i < 10; ++i){
		printf("char: %c\n", memory[i]);
	}
	return 0;
}

My problem is as follow:
When I use the strcpy function in the main to copy my string in the memory this works. My string "test" is nicely placed in the memory. But when I use

Code:

string ="test"

this isn't placed in the memory and the values in the memory are still on the initialized values.

What am I doing wrong?