Thread: Copying portions of arrays?

I am currently taking a C class, and I have been assigned to

1. Prompt the user and accept a string of no more than 254 characters
2. Prompt the user and accept a second string of no more than 254 characters
3. Create a third string consisting of the first half of string (1) and the second half of string (2). Display this string

I know how to prompt for strings, but I'm having a little difficulty figuring out what tools I should use for this. I'm thinking that if I could get the length of the strings, I could divide the numbers in two, and I could use those numbers to create a loop and display the characters using < & >. However, I don't know how I would do this, or even if this is the correct method. Any help would be greatly appreciated.

Thank you! It helped, and I was able to pull it off. However, I have a new issue. I'm trying to get a character count, and I'm having an issue with any showing up. Perhaps you could help me with what I'm messing up on:

Code:

#include <stdio.h>#include <stdlib.h>
#include <string.h>






int main()
{
    char str1[255], str2[255], combinedStr [255], newSentence [101];
    int lenOfStr1, lenOfStr2, lenOfNewSent, newSentenceArray [128]={0}, totalArray [128]={0};
    char currentChar, currentChar2;
    int i = 0, totLtrs = 0;
    double percentage = 0.00;


    printf("Please enter a string of 254 characters or less:");
    fgets(str1,254,stdin);
    printf("Please enter a second string of 254 characters or less:");
    fgets(str2,254, stdin);
    lenOfStr1 = strlen (str1);
    lenOfStr2 = strlen (str2);
    str1[lenOfStr1 - 1] = '\0';
    str2[lenOfStr2 - 1] = '\0';
    printf("Your first  string is %d characters long.\n", lenOfStr1);
    printf("Your second string is %d characters long.\n", lenOfStr2);
    strncpy(combinedStr, str1, lenOfStr1 / 2);
    combinedStr[lenOfStr1 / 2] = '\0';
    strcat(combinedStr, str2 + lenOfStr2 / 2);
    printf("String 3 is %s\n", combinedStr);
    printf("Now, please enter a sentence of up to 100 characters:");
    fgets(newSentence, 100, stdin);


    lenOfNewSent = strlen (newSentence);
    newSentence[lenOfNewSent - 1] = '\0';


    while (newSentence[i] != '\0')
    {
        currentChar = newSentence[i];
        newSentenceArray[currentChar]++;
        ++i;
    }


    totLtrs = i;


    printf("\nFor the string you just wrote\n\n\n", i);
    printf("FREQUENCY TABLE\n-------------------\nChar   Count   %% of Total\n");
    printf("----   -----   ----------\nALL\t%d\t100.00%%\n", totLtrs, percentage);


    for (i=0; i < 128; ++i)
    {
        if (newSentenceArray[i] > 0)
        {
            printf("'%c'\t%d\t%-2.2f%%\n", i, newSentenceArray[i], percentage = ((double) newSentenceArray[i]/(double) totLtrs) * 100.00);
        }
    }


    strcpy (combinedStr, str1);
    strcat (combinedStr, str2);
    strcat (combinedStr, newSentence);
    lenOfNewSent = strlen (combinedStr);
    combinedStr[lenOfNewSent - 1] = '\0';
    i=0;


    printf("The new combinesStr is %s", combinedStr);




    while (combinedStr[i] != '\0')
    {
        currentChar2 = totalArray[i];
        totalArray[currentChar2]++;
        ++i;
    }


    totLtrs = i;
    printf("i is %d", i);


    printf("\nFor everything you've written\n\n\n");
    printf("FREQUENCY TABLE\n-------------------\nChar   Count   %% of Total\n");
    printf("----   -----   ----------\nALL\t%d\t100.00%%\n", totLtrs);


    for (i=0; i < 128; ++i)
    {
        if (totalArray[i] > 0)
        {
            printf("'%c'\t%d\t%-2.2f%%\n", i, totalArray[i], percentage = ((double) totalArray[i]/(double) totLtrs) * 100.00);
        }
    }










    return 0;
}

The first loop works perfectly, but I can't get anything with the second. Any ideas?

Check line 80. You're probably using the wrong array.

Bye, Andreas

Originally Posted by AndiPersti

Check line 80. You're probably using the wrong array.

Bye, Andreas

What? No, I checked that out a dozen times last ni.... ohhhhHHHHHHHHHHHHHHH ARRGGGHHHHH!!!!!!

HOW COULD I HAVE MISSED THAT??!!!!!

*clears throat*

Thank you, that was quite helpful.