Simple pointer function question

[ilerleartik]

Hi,

I struggled on something; here is the question;

I have a struct that contains some items and a pointer; I call this node;
I have another node in same struct and also have a pointer.

Now these two nodes are linked with a next pointer just as you know as linked list.

I want to do move to another linked list from the first one. (temp is a struct pointer)

temp=firstnode;
temp=temp->next;

It is ok, but when I want to do this with a function;

void myfunction(mystruct *tmp)
{
tmp=tmp->next;
}
...
..
myfunction(temp); //in main(), call the function

it fails, what am I missing? Isnt it already a "call by referance"? why doesnt temp move another node?

Thanks in advance.

[ilerleartik]

I tried this and worked, I don't know why;

void myfunction(mystruct **tmp)
{
*tmp=(*tmp)->next;
}
..
.
..
myfunction(&temp); //in main(), call the function

I really don't know what happened and why it worked, can someone explain how?

[Ocifer]

Passing a pointer to a function, say a pointer to an integer variable, allows you to change the value of the integer variable pointed to by that pointer.

In your first code you posted, you were passing a pointer (aka some variable), changing its value in the function, and then that changed nothing outside the scope of your function.

// Corrections, comments welcomed.