Thread: How to convert character into integer?

Basically my program specifications require that I NOT use arrays.
I want to convert a string into its integer values. For example
printf("Please enter a word");

How would i scanf each indivudual character the user inputs?

Code:

printf("Please enter a word");
scanf(
printf("The total value of the characters are: );

To read a single character, use the function getchar().

You don't store values. The description specifically forbids the use of arrays.
Where would you store the characters? ???

Read them, one by one, and deal with them, again one by one.

Originally Posted by qny

You don't store values. The description specifically forbids the use of arrays.
Where would you store the characters? ???

Read them, one by one, and deal with them, again one by one.

I think i almost have it.

Code:

int main()
{
printf("Line: ");
char mynum;
scanf("%c",&mynum);







while(mynum!='.')
{

While the input is not '.', how would i add up the values?

let's say input is 'This'

So ... answer me this:
what is the value of "This"?
Or what output do you expect for an input of "This"?

EDIT: This assumes you want to total up the numeric values associated with each character the user inputs:

A char is just like a tiny little int. We tend to think of them as being letters/punctuation, and express them as 'T', 'h', etc, but they do have numeric values. Take a look at an ASCII chart (link) for an example of one mapping of letters to numbers (there are others, but they're much less common, and you are almost certainly not using them).

That means mynum is already a number, so you just add it to some other variable that keeps track of the sum. Make that other variable a regular int, so there's room to total up all the chars.