Linked List won't print

**ch4** · 10-31-2012

The very fisrt step before add a node is to initialize the head/last pointers to NULL propably into main.
Decide the way new items should be inserted to list. (Let's say at the end)
In the beggining (empty list) head and last are pointing to the same node (aka NULL)
Adding an item:
1. Store the new value to an int
2. Allocate memory (malloc) of the new node to temp pointer. Initialize it. (temp->next = NULL, value = 0 etc)
3a. if this is the first time adding item then, both head/last pointers should point to temp and next pointer of temp to NULL
3b. else, next pointer of last node should point to temp and next of temp should point to NULL.
4. Copy the new value and return new node

The fifth rule : A real programmer doesn't eat until debugging ends.

Attachment 12139

**jrclark** · 10-31-2012

Just got back from lunch here is Lab8.h...while I read all the replies.

Code:

struct node
{
    int value;
    struct node *next;
};


struct node *add();
void print(struct node *list);
void _delete(int v);
struct node *find(int v);
void menu();

**std10093** · 10-31-2012

Originally Posted by jrclark

Just got back from lunch here is Lab8.h...while I read all the replies.

In my opinion i would say that it is better to post all your replies in one post.
For example, when you read the answers you are going to post again.So why not enclose the information in one package and enclose it in two?

**jrclark** · 10-31-2012

Originally Posted by std10093

In my opinion i would say that it is better to post all your replies in one post.
For example, when you read the answers you are going to post again.So why not enclose the information in one package and enclose it in two?

Good thing everyone is entitled to there own opinion.

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