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Printing a certain number of variables.

This is a discussion on Printing a certain number of variables. within the C Programming forums, part of the General Programming Boards category; Is there an easier way to do this? The quantity is decided in the program. I don't know how it ...

  1. #1
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    Printing a certain number of variables.

    Is there an easier way to do this? The quantity is decided in the program. I don't know how it is done with a loop if it's possible. If there's more than one way, can you please briefly describe all of them? Thank you.
    Code:
    void printSorted( int quantity, int n1, int n2, int n3, int n4, int n5, int n6 )
    {
        switch( quantity )
        {
            case 1:
                printf( "%d", n1 );
                break;
            case 2:
                printf( "%d, %d", n1, n2 );
                break;
            case 3:
                printf( "%d, %d, %d", n1, n2, n3 );
                break;
            case 4:
                printf( "%d, %d, %d, %d", n1, n2, n3, n4 );
                break;
            case 5:
                printf( "%d, %d, %d, %d, %d", n1, n2, n3, n4, n5 );
                break;
            case 6:
                printf( "%d, %d, %d, %d, %d, %d", n1, n2, n3, n4, n5, n6 );
                break;
        }
    }

  2. #2
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    Arrays are designed for situations like this.

    Arrays in C and C++ - Cprogramming.com
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  3. #3
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    Can it be done without using an array?

  4. #4
    TEIAM - problem solved
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    Using an array IS the easiest and neatest way.

    If you wanted to do different without using an array, you could do something like this:
    Code:
    void printSorted( int quantity, int n1, int n2, int n3, int n4, int n5, int n6 )
    {
        if (quantity < 1) return;
    
    
        printf( "%d", n1 );
    
    
        if (quantity < 2)  return;
    
    
        printf( ", %d", n2 );
    
    
        if (quantity < 3)  return;
    
    
        printf( ", %d", n3 );
    
    
        if (quantity < 4)  return;
    
    
        printf( ", %d", n4 );
    
    
        if (quantity < 5)  return;
    
    
        printf( ", %d", n5 );
    
    
        if (quantity < 6)  return;
    
    
        printf( ", %d", n6 );
    
    
    }
    However, it is not as good as using an array and a loop.
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  5. #5
    qny
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    Or use function with a variable number of arguments (I still prefer the array solution)

    Code:
    #include <stdarg.h>
    #include <stdio.h>
    
    void printSorted(int quantity, ...) {
      va_list ap;
      int k;
      va_start(ap, quantity);
      printf("%d", va_arg(ap, int));
      for (k = 1; k < quantity; k++) {
        printf(" %d", va_arg(ap, int));
      }
      va_end(ap);
      puts("");
    }
    
    int main(void) {
      printSorted(2, 42, 42);
      printSorted(15, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3);
      return 0;
    }

  6. #6
    Algorithm Dissector iMalc's Avatar
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    Quote Originally Posted by HaydeezPluto View Post
    Can it be done without using an array?
    That's like asking if you can run a marathon by hopping all the way on one leg. In theory maybe, but in practice that would be idiotic.
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