Thread: Series output problem

I need to print the following series :

1-1/2+1/3-1/4......+-1/n

where n will be given by user.

I have written the code as :

Code:

int main()
{
     int i,n;
     float sum=0.0;
     printf("\n Enter the no. of terms for summation : ");
     scanf("%d",&n);
     for(i=1;i<=n;i++)
       {
           if(i%2==0)
              i=-i;
           sum=sum+1.0/i;
       }
     printf("\n Summation is : %4.2f",sum);
     
     return 0;
 }

Only for n=1 I am getting an output, but frm n=2 onward no output.

Please tell me where i am going wrong.

Code:

for(i=1;i<=n;i++)
...
              i=-i;

What do you think is going to happen to your for loop, if you negate i ?

Oppss....That was a pathetic mistake i made..!!!

Try this code and see what happens

Code:

int sign = 1;
for ( i = 0 ; i < 10 ; i++ ) {
    printf("Sign = %d\n", sign );
    sign = -sign;
}

Thankss Salem...It worked out beautifully for me...Thank u so so much...