How do you end a program if conditions don't match?

[tmac619619]

[code]

 while(bread_type!='w && bread_type!='W')
 {
    printf("Please enter a valid character");
 
 
  }

Basically what happens next is my program "crashes" and prints "Please enter a valid char" infinitely.

[Adak]

You're telling them to enter a valid character and then you're closing the program anyway?

You could use exit(1), beneath the printf() statement, but it sounds wrong to end a program right after requesting a char.

[tmac619619]

Oh right. So i should use a loop to keep prompting the user to enter the correctchar right?

 while(bread_type!='w && bread_type!='W')
 {
    printf("Please enter a valid character");
 
 
  }

Uhmm basically i want to keep prompting the user till they enter the correct character.
but my program crashes.. in an endless "Please enter a valid character" loop

[iMalc]

Take a long hard look at your if statement. It can never be false since everything is either not 'w' or not 'W'.

[Adak]

Oh right. So i should use a loop to keep prompting the user to enter the correctchar right?

 while(bread_type!='w && bread_type!='W')
 {
    printf("Please enter a valid character");
 
 
  }

Uhmm basically i want to keep prompting the user till they enter the correct character.
but my program crashes.. in an endless "Please enter a valid character" loop

A while() loop is a bit awkward for this. Consider a do while loop:

do {
   printf("Please enter a valid character [w,d,r]: ");
   scanf(" %c",&mychar);
   mychar=tolower(mychar);
}while(mychar != 'w' && mychar != 'd' && mychar != 'r');

The difference is the naturalness of a test at the end of the loop, instead of at the beginning. This is when the loop will always be entered, at least once. A while loop may or may not be entered.