Program skips condition which uses argv[]

[Unregistered]

Basically, I'm creating a command line program that performs a Caesar Cypher using the entire ASCII table. Now I can get it to encrypt, but it doesn't decrypt for some reason.

I'm not really sure if this conditional statement is correct, so that might be the issue.

if ((argc == 4) && (argv[1] == "-d")){
    i = 1;
    offset = 2;

    printf("About to encrypt file...\n");
    inFile = fopen(argv[2], "r");
    outFile = fopen(argv[3], "w");
    printf("The files have been opened.\n");

    if (inFile == NULL) {
      printf("Unable to open %s\n", argv[2]);
      exit(1);
    }

    if (outFile == NULL) {
      printf("Could not open %s\n", argv[3]);
      exit(1);
    }

   while ((current = fgetc(inFile)) != EOF){
      printf("Scanning file %s\n", argv[2]);
      printf("Printing decrypted %c to %s\n", current, argv[3]);
      nRep = (int)current;
      if (nRep - (offset + i) < 0) nRep = (128 + (nRep - (offset + i)));
      else nRep = (nRep - (i + offset));
      current = (char)nRep;
      fprintf(outFile, "%c", current);
      i++;
    }
      fclose(inFile);
      fclose(outFile);
  }

Now I had a debug statement in my program to display what argv[1] was, and it would show -d. Yet, the encryption function would still get satisfied somehow and it would encrypt the already encrypted file instead.

Any help would be greatly appreciated

[Salem]

> argv[1] == "-d")){
Should be
strcmp(argv[1],"-d") == 0

[Unregistered]

Phew! That fixed it.

Thank you very much for your help Salem!