"Write and call a function that displays instructions to the user"

[tmac619619]

I'm a little bit confused. Usually a function looks like this

I'm little bit confused so a function usually looks like this right?

name (int x,int y);

How can i make it so that the function displays instructions?
name (printf); ?


where printf contains the instructions?

[bluechip]

What you can do is declare a function and make it accept a character array and output the array. Then call the function and pass a pointer to an initialised character array to the function.

[tmac619619]

hmm so i did this in the prototype

void instructions(void);

Now how would i "call" the function in main?

[Matticus]

I appears that you're just supposed to put a "print" statement within a function (that you're to write yourself) and call that function from "main()". I'm sure you're over-thinking this assignment.

[Matticus]

hmm so i did this in the prototype

void instructions(void);

Now how would i "call" the function in main?

The same way you would call any function from "main()".

[tmac619619]

Well the assignment is pretty simple. Input output. With a little bit of calculations.

But its just that the "Write and call a function that displays instructions to the user is throwing me off"

int main()

curly bracket

printf("instructions");

curly bracket

[bluechip]

With the prototype u wrote, it means the function 'instruction' is not returning any value and it is not accepting any arguments. Since u want the function to display information, it must accept an argument. So, your prototype is wrong.
Try something like this:

   int main(void) {
    char name[] = "Hello World!";
    /*call the function*/
   instruction(name);
   }

  void instruction(char x[]) 
 {
    printf("%s",x);
 }

[Matticus]

The "print" statement has to be within a function. If you don't fully understand functions, you can read about them here.

Or, to see a full [small] program that uses functions to add two numbers, refer to my post #4 here. Only, instead of adding and returning a value, you'll be printing instructions.

[Matticus]

@bluechip: It seems that the required function can print the information without any arguments, as arguments were not specified in the assignment. When I write a "menu" function, I don't pass information to it - all menu items are included in that function (though it does return the value selected by the user).

[bluechip]

@matticus: The function needs arguments, so that it will be able to print the content of any character array and as such any instruction

[camel-man]

You just need a function that prints instructions? Then you must realize that void is your best choice. You are not returning anything, therefore your return type is void. No arguments being passed so therfore you can use void there too. void foo(void); <---- Theres a nice start to a function.

[oogabooga]

@bluetooth: You are obviously a raw beginner. Do you really think it's appropriate for you to "answer" questions?

If you read the OPs posts (and understand English) you will see that Matticus is correct.