warning on wprintf

problem solved code removed

Solution : bypass wprintf by using mbstowcs and then printf

Try for example

Code:

wprintf(L"%d: %s\n", words[i].freq, s);
//      ^ L for wchar_t string

Originally Posted by qny

Try for example

Code:

wprintf(L"%d: %s\n", words[i].freq, s);

I hadn't the L so this might be it,but already bypassed it

You should know better than to remove code from the original post! This prevents others in the future seeing a similar problem from finding a solution.

Not my code and i do not like it,but ok,i'll edit

Can not so post here

Code:

#include <assert.h>
#include <string.h>
#include <stdio.h>
#include <wchar.h>
#include <locale.h>

typedef struct {
    wchar_t term[10];
    int freq;
} word_t;

/* global array of words */
word_t words[5000];
int n_words = 0;

int find_word(wchar_t s[]) {
    int i;
    for (i=0; i < n_words; i++)
        if ((wcslen(s) == wcslen(words[i].term)) && wcsncmp(s, words[i].term,10) == 0)
            return i;
    return -1;
}

void add_word(wchar_t s[]) {
    assert(wcslen(s) <= 10);
    wcsncpy(words[n_words].term, s,10);
    words[n_words].freq = 1;
    n_words++;
}

int main(void) {
    wchar_t s[11];
    wint_t c;
    int i;
    int counter = 0 ;/*use in inserting characters in s*/
    setlocale(LC_CTYPE,"UTF-8");
    printf("Please type a word with 10 characters at most\n");
    while (( c = getwchar() ) != WEOF) {
        if( counter > 10 )
        {
            printf("Word with more than 10 characters detected,so exiting...\n");
            return -1;
        }
        if( c != '\n' )
        {
            s[counter++] = c;
        }
        else
        {
            i = find_word(s);
            if (i == -1)
            {
                add_word(s);
                /*wprintf(L"1: %0.10ls\n", s);*/
            }
            else
            {
                words[i].freq++;
                /*wprintf(L"%d: %0.10ls\n", words[i].freq, s);*/
            }
            for( i = 0 ; i < 11 i++)/*clear the buffer*/
            {
               s[i] = '\0';
            }
            counter = 0;/*reset counter*/

            printf("Please type a word with 10 characters at most\n");
        }
    }
    for( i = 0 ; i < n_words ; i++)
    {
        wprintf(L"%d: %0.10ls\n", words[i].freq, words[i].term);
    }
    return 0;
}