Thread: Vector buildings and Box Muller transform

Hi guys, I got 2 problems:

• I need to build an array that has a function similar to a triangle. My function goes from -40 to 40 with steps of 0.002. So it has to be a 40000 elements array, made like that:

var filler goes from -40 to 40 with step of 0.002


function is, for each element:
(40.0-fabs(filler))/40.0

so I expect my triangle starting from o (40-|-40|)/40=0/40=0, with an apex of (40-0)/40=1, and getting back to 0 at the end.

Here is how I implemented it:

Code:

filler=-40.0;
    for(i=0;i<40000;i++){
        VettoreIniziale[i].img=0.0;
        VettoreIniziale[i].real=(40.0-fabs(filler))/40.0;
        filler+=0.002;
          }

It starts from 0.0000 but it has an apex of about 0.998 and end with a negative number, like -0.004.. Why it happens? What did I do wrong?

• Second problem. I need to fill an array with random numbers in the range [-1,1] with mean = 0 and variance =1. I tried to use Box Muller transform, but it gives me strange results... Here the main and the method.

Box Muller

Code:

#include <stdlib.h>double rand_normal(double mean, double stddev) {
    static double n2 = 0.0;
    static int n2_cached = 0;
    if (!n2_cached) {
        double x, y, r;
do {
   x = 2.0*rand()/RAND_MAX - 1;
y = 2.0*rand()/RAND_MAX - 1;
    r = x*x + y*y;
} while (r == 0.0 || r > 1.0);
        {
        double d = sqrt(-2.0*log(r)/r);
double n1 = x*d;
n2 = y*d;
        double result = n1*stddev + mean;
        n2_cached = 1;
        return result;
        }
    } else {
        n2_cached = 0;
        return n2*stddev + mean;
    }
}

This is the main code regarding it:

Code:

#include <stdio.h>
#include <stdlib.h>
#include "MISC.h"
#include <math.h>
#include <time.h>

...
srand(time(NULL));
...

for(i=0;i<LENGTH;i++){        GaussianWhiteNoise[i].real=(float)rand_normal(0.0,1.0);
        GaussianWhiteNoise[i].img=0.0;
        printf("%d %3.4f \n",i,GaussianWhiteNoise[i].real);

I tried not to use (float) to convert, but it happens the same.

This is the output...

0 4.0000
1 2665544.0000
2 4.0000
3 2665544.0000
4 0.0000
5 2665544.0000
6 0.0000
7 2665544.0000
8 0.0000
9 2665544.0000
10 0.0000
11 2665544.0000
12 0.0000
13 2665544.0000
14 0.0000
15 2665544.0000
16 0.0000


etc etc

Don't care about 2nd problem. I forgot to put function prototype on the main -.-

Thank you very much, you've been very kind

It can be closed if necessary.