Error with my function

Here is my function:

Code:

 
void Display_Info(clock_num,  wage_rate, clock_hours,  overtime_hours,  gross_pay)
{
    int count;     /* Variable used for loop counter */

    /* Create table to display employee information */
        printf("\n------------------------------------------------\n");
        printf("Clock#      Wage     Hours     OT      Gross\n");
        printf("------------------------------------------------\n\n");

        /* print employee information from arrays into table */
        for (count = 0; count < SIZE; count++)
            printf("%06li     %5.2f    %5.1f   %5.1f    %7.2f\n", clock_num[count] , wage_rate[count] , clock_hours[count] , overtime_hours[count],  gross_pay[count]);
}

and here is my call within main

Code:

 
Display_Info(clock_num, wage_rate, clock_hours, overtime_hours, gross_pay);

I am getting subscripted value is neither an array or pointer on line 12. I am not sure what to do and as per directions, I am not to use pointers. How can I fix this?

You are missing the parameter types. You should be getting warnings about that.

Originally Posted by iMalc

You are missing the parameter types. You should be getting warnings about that.

lol what does that mean?

lol nevermind.. I just had a severe brain fart.

Code:

void Display_Info(clock_num,  wage_rate, clock_hours,  overtime_hours,  gross_pay)

You need to mention the types for all the function parameters in here. Otherwise default types would be assumed by the compiler and probably thats causing the trouble.