Hello,

This program that is supposed to find pi, and it should approximate pi to some number of terms. This number is an input from user. However, for some reason, when I run it and enter 10 as my input, it doesn't do anything. No error, no return. Here is a screenshot of what I am stuck at.

Code:#include <stdio.h> #include <stdlib.h> #include <math.h> long double approx1 (int terms); long double approx2 (int terms); int main () { long double pi, first, second; int terms; char ch; printf ("\nEnter the number of terms to approximate pi, or 0 to terminate: "); scanf ("%d", &terms); while (terms != 0) { if (terms == 1) { pi = 4; printf ("\nFirst approximation of pi to 1 term is %.8Lf\n\n", pi); pi = sqrt(12); printf ("Second approximation of pi to 1 term is %.8Lf\n\n", pi); } else if (terms > 1 ) { first = approx1 (terms); printf ("\nFirst approximation of pi to %d term is %.8Lf\n\n", terms, first); second = approx2 (terms); printf ("Second approximation of pi to %d term is %.8Lf\n\n", terms, second); terms = 0; } else { printf ("\nWrong input, please try again\n\n"); } printf ("Enter the number of terms to approximate pi, or 0 to terminate: "); scanf ("%d", &terms); } printf ("\n\n***** Program Terminated *****\n"); return 0; } long double approx1 (int terms) { int i; long double pi=0,denom=1.0,num=4.0; for ( i =1; i = (terms+1); i++) { if ((i % 2) != 0) { pi = pi + (num / denom); } else { pi = pi - (num / denom); } denom = denom + 2.0; } return pi; } long double approx2 (int terms) { int i; long double pi=0.0,denom = 1.0,num=12.0; for ( i =1; i = (terms+1); i++) { if ((i % 2) != 0) { pi = pi + (num / denom); } else { pi = pi - (num / denom); } denom = (denom + 1.0)*(denom +1.0); } pi = sqrt(pi); return pi; }