Please correct my code to work....Code:main() { int a[10][5],j,i; for(j=0;j<5;j++) for(i=0;i<10;i++) scanf("%d",&a[i][j]); prior(a,j); return 0; } int prior(int a[][],int j) { int m=-1,p,k,c[100]; for(p=0;p<j;p++) for(k=0;k<3*n;k+3) { m=m+1; c[m]=a[k][i]-(a[k+1][i]+a[k+2][i]); } return c[];
The easiest thing to do is pass in the array where you want the results stored.
Eg.
Code:void prior( int a[][5], int c[], int j); int main ( ) { int a[10][5], c[100]; prior(a,c,j); }
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
How can I return a 1-D array c[100]?Originally Posted by Salem
You just do things like
c[0] = 0;
inside your function, and that will make the change in the array declared in main.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
Also, you haven't declared n or i and there is a missing '}' in your prior function ( the '}' is more likely a "copy and paste" problem)
Fact - Beethoven wrote his first symphony in C
