Function: passing 2-D array and returning a 1-D array from a function

Code:

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main()
{
    int a[10][5],j,i;
for(j=0;j<5;j++)
    for(i=0;i<10;i++)
              scanf("%d",&a[i][j]);
       
prior(a,j);
return 0;
}
int prior(int a[][],int j)
 {
    int m=-1,p,k,c[100];
    for(p=0;p<j;p++)
    for(k=0;k<3*n;k+3)
    {
        m=m+1;
        c[m]=a[k][i]-(a[k+1][i]+a[k+2][i]);
    }
return c[];

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Please correct my code to work....

The easiest thing to do is pass in the array where you want the results stored.
Eg.

Code:

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void prior( int a[][5], int c[], int j);
int main ( ) {
    int a[10][5], c[100];
    prior(a,c,j);
}

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Quote:

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Originally Posted by Salem

The easiest thing to do is pass in the array where you want the results stored.
Eg.

Code:

---

void prior( int a[][5], int c[], int j);
int main ( ) {
    int a[10][5], c[100];
    prior(a,c,j);
}

---

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How can I return a 1-D array c[100]?

You just do things like
c[0] = 0;
inside your function, and that will make the change in the array declared in main.

Also, you haven't declared n or i and there is a missing '}' in your prior function ( the '}' is more likely a "copy and paste" problem)