Function: passing 2-D array and returning a 1-D array from a function

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• 09-24-2012
enakta13
Function: passing 2-D array and returning a 1-D array from a function
Code:

```main() {     int a[10][5],j,i; for(j=0;j<5;j++)     for(i=0;i<10;i++)               scanf("%d",&a[i][j]);         prior(a,j); return 0; } int prior(int a[][],int j)  {     int m=-1,p,k,c[100];     for(p=0;p<j;p++)     for(k=0;k<3*n;k+3)     {         m=m+1;         c[m]=a[k][i]-(a[k+1][i]+a[k+2][i]);     } return c[];```
Please correct my code to work....
• 09-25-2012
Salem
The easiest thing to do is pass in the array where you want the results stored.
Eg.
Code:

```void prior( int a[][5], int c[], int j); int main ( ) {     int a[10][5], c[100];     prior(a,c,j); }```
• 09-25-2012
enakta13
Re:Function: passing 2-D array and returning a 1-D array from a function
Quote:

Originally Posted by Salem
The easiest thing to do is pass in the array where you want the results stored.
Eg.
Code:

```void prior( int a[][5], int c[], int j); int main ( ) {     int a[10][5], c[100];     prior(a,c,j); }```

How can I return a 1-D array c[100]?
• 09-25-2012
Salem
You just do things like
c[0] = 0;
inside your function, and that will make the change in the array declared in main.
• 09-25-2012
Click_here
Also, you haven't declared n or i and there is a missing '}' in your prior function ( the '}' is more likely a "copy and paste" problem)