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datatype deduction

This is a discussion on datatype deduction within the C Programming forums, part of the General Programming Boards category; I am unable to understand mam,what you say... I am quite new to C...

  1. #16
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    I am unable to understand mam,what you say...
    I am quite new to C

  2. #17
    C++ Witch laserlight's Avatar
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    Well... here's an example:
    Code:
    #include <stdio.h>
    
    int main(void)
    {
        int a[2];
        printf("For integer data type: Bytes stored = %d\n", (char*)&a[1] - (char*)&a[0]);
        return 0;
    }
    If you still don't understand this or why it works, then I suggest that you leave this trivia question aside for the time being and continue learning to program in C.
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  3. #18
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    Thanks a lot for your code and suggestions.
    But truely I do not understand it til now...
    But it working fine fine

    Thanks a tonne!

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