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Out of this program?How?

This is a discussion on Out of this program?How? within the C Programming forums, part of the General Programming Boards category; Code: main() { int i; for(i=1;i<=5;printf("\n%d",i)); i++; } Actually I meant "output* of this program?How?" Why am I getting an ...

  1. #1
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    Out of this program?How?

    Code:
    main()
    {
    int i;
    for(i=1;i<=5;printf("\n%d",i));
    i++;
    }
    Actually I meant "output* of this program?How?"
    Why am I getting an indefinite loop of 1?
    Last edited by sameertelkar; 09-15-2012 at 03:58 AM.

  2. #2
    C++ Witch laserlight's Avatar
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    Notice the semi-colon at the end of the for loop. As such, your for loop has an empty body.

    Oh, and you should explicitly declare main as returning an int.
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

  3. #3
    qny
    qny is offline
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    Because of the extra semi-colon your program is the same as
    Code:
    main()
    {
    int i;
    
    for(i=1;i<=5;printf("\n%d",i)) { /* do nothing */ }
    
    i++;
    }
    The for loop never ends: it's an infinite loop.
    sameertelkar likes this.

  4. #4
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    Thank you to you both.I think I got it.

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