Code:

#include <stdio.h>
#define EOL '\0'


int main(int argc, const char * argv[])
{
 char sent[50];
 int i=0;
 int cnt=0;
 char charac;

puts("Please enter a sentence");
 scanf(" %[^\n]",sent);

    puts("Please enter the character to be checked");
    charac=getchar();

 while (sent[i]!=EOL) {


 if(sent[i]==charac)
        {
            ++cnt;
            ++i;
        }
 else
            ++i;


    }

printf("\nCHARACTER OCCURRED %d TIMES",cnt);


return 0;
}

hey guys,
I'm trying to write a program that accepts a character from the user to compute the number of times the character appears in an inputted sentence. However, the compiler completely ignores the
getchar function. So i tried putting the getchar function above the scanf and this time it works!!
Can anyone explain this???

Q: what is the last character you typed for the sentence?
A: an ENTER

That ENTER is what getchar() gets.

Suggestion: use fgets() instead of scanf() to read the sentence.

hmm i haven't started on files yet but thank you very much for replying

Originally Posted by qny

Suggestion: use fgets() instead of scanf() to read the sentence.

Originally Posted by abeljohny

hmm i haven't started on files yet but thank you very much for replying

We have a FAQ for that: FAQ > Get a line of text from the user/keyboard (C) - Cprogramming.com.

Note that the file they pass to fgets is stdin, which is the standard input device (your keyboard). So that call to fgets reads from the keyboard.