Nested if question.

This is a discussion on Nested if question. within the C Programming forums, part of the General Programming Boards category; Code: /*program 3.3 using nested ifs to analyze numbers*/ #include <stdio.h> #include <limits.h> /*for LONG_MAX*/ int main() { long test ...

  1. #1
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    Question Nested if question.

    Code:
    /*program 3.3 using nested ifs to analyze numbers*/
    #include <stdio.h>
    #include <limits.h>/*for LONG_MAX*/
    
    int main()
    {
        
    long test = 0L;         /*stores the integer to be checked*/
        printf("Enter an integer less than %ld:", LONG_MAX);
        scanf("%ld", &test);
        
    /*test for odd or even by checking the remainder after dividing by 2*/
        
    if(test % 2L == 0l)
        {
            printf("The number %ld is even", test);
            
    /*now check whether half the number is also even*/
            
    if( (test/2L) % 2L == 0L)
            {
                printf("\nHalf of %ld is even", test);
                printf("\nThat's interesting isn't it?\n");
            
    else
                printf("\n Half of %ld is odd\n", test);
            }
        }
        
    else
            printf("The number %ld is odd\n", test);
    }
    
    Im getting and error because it says that the else statement: printf( "\n Half of %ld is odd\n", test); has no matching if. Is there a way I can still keep that else branch nested within the bigger if-else?

  2. #2
    SAMARAS std10093's Avatar
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    Α bracket '}' is missing at line after printf("\nThat's interesting isn't it?\n");
    That is what you want?
    Last edited by std10093; 07-24-2012 at 05:23 PM.

  3. #3
    SAMARAS std10093's Avatar
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    Actually with a second look i suggest this

    Code:
    int main(void)
    {
        
    long test = 0L;         /*stores the integer to be checked*/
        printf("Enter an integer less than %ld:", LONG_MAX);
        scanf("%ld", &test);
        
    /*test for odd or even by checking the remainder after dividing by 2*/
        
    if(test % 2L == 0l)
        {
            printf("The number %ld is even", test);
            
    /*now check whether half the number is also even*/
            
    if( (test/2L) % 2L == 0L)
            {
                printf("\nHalf of %ld is even", test);
                printf("\nThat's interesting isn't it?\n");
    }
            
    else
                printf("\n Half of %ld is odd\n", test);
            
        }
        
    else
            printf("The number %ld is odd\n", test);
    return 0;
    }
    Is it ok?

  4. #4
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    yes, thats good sloves my problem. Thanks!

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