Data sorting with tab delimited .txt input file

This is a discussion on Data sorting with tab delimited .txt input file within the C Programming forums, part of the General Programming Boards category; 0 0 15.5 15.5 -29.671 81.879 0.149821 -0.207526 0.000906136 -0.00125514 0.00154805 0 1 0 39.5 15.5 -28.7275 81.879 0.241249 -0.199974 ...

  1. #1
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    Arrow Data sorting with tab delimited .txt input file

    0 0 15.5 15.5 -29.671 81.879 0.149821 -0.207526 0.000906136 -0.00125514 0.00154805 0
    1 0 39.5 15.5 -28.7275 81.879 0.241249 -0.199974 0.0014591 -0.00120947 0.0018952 0
    2 0 63.5 15.5 -27.784 83.879 0.113511 -0.208251 0.00068653 -0.00125952 0.00143448 0
    3 0 87.5 15.5 -26.8405 83.879 0.262949 -0.119694 0.00159035 -0.000723924 0.00174736 0
    4 0 111.5 15.5 -25.897 86.879 0.340391 -0.153879 0.00205873 -0.000930676 0.00225932 0
    5 0 135.5 15.5 -24.9535 86.879 0.350416 -0.0832607 0.00211936 -0.00050357 0.00217836 0
    6 0 159.5 15.5 -24.01 88.879 0.237944 -0.0505043 0.00143911 -0.000305456 0.00147117 0
    7 0 183.5 15.5 -23.0665 88.879 0.416603 -0.074264 0.00251966 -0.000449157 0.00255938 0
    8 0 207.5 15.5 -22.1229 89.879 0.442096 -0.140521 0.00267384 -0.00084989 0.00280567 0
    9 0 231.5 15.5 -21.1794 89.879 0.599385 -0.0447657 0.00362515 -0.000270748 0.00363524 0



    Above is my test.txt file, tab delimited. I would want my program to read that file, and pull a few columns to new file lets say output.txt (I haven't code that in my program yet, can ignore that first). I want to pull data from column 5, 6, and 10, and rearrange it in output.txt as column 6, 10, 5 (which is working, ignore the file output part). The problem is, I just want to pick the data from column 5 which the value equals to lets say 86.879, and the output data should look like this:


    86.879 -0.000930676 -25.897
    86.879 -0.00050357 -24.9535


    How can I get it done? Below is my coding. Thanks in advance!


    Code:
    #include <stdio.h>
    #include <stdlib.h>
    
    
    int main()
    {
    
    
       static const char filename[] = "test.txt";
       FILE *file = fopen(filename, "r");
    
    
       if ( file != NULL )
       {
          signed char *line[BUFSIZ];
    
    
       signed char col5[BUFSIZ], col6[BUFSIZ], col10[BUFSIZ], col6x[BUFSIZ];
    
    
     // remove the slashes             printf("Data fetch coordinate x[mm]: ");
     // remove the slashes           scanf("%d", &col6x);
    
    
          while ( fgets(line, sizeof line, file) != NULL )
          {
             if ( sscanf(line, "%*s %*s %*s %*s %s %5s %*s %*s %*s %s", &col5, &col6, &col10) == 3 )
               {
          if ( col6x == col6 )
          {
            printf("%s\t%s\t%s\n", col6, col10, col5);
          }
               }
    
    
       } 
       system("pause");
       }
       else
       {
          perror(filename);
       }
       return 0;
    }

  2. #2
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    Complied and tried to enter 86.879 or 86.87 (with the slashes removed in the code), it returned nothing.

  3. #3
    and the hat of wrongness Salem's Avatar
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    > signed char *line[BUFSIZ];
    You want an array of char, not an array of char pointers.
    So
    signed char line[BUFSIZ];

    > if ( sscanf(line, "%*s %*s %*s %*s %s %5s %*s %*s %*s %s", &col5, &col6, &col10) == 3 )
    1. Drop the & from all the variables. An array name is already a pointer to a char, so nothing is gained by using &.
    If the variables were really pointers to begin with, then using & would be very wrong indeed.
    2. Why %5s when the string itself is already 6 chars long? All it does is make it harder - the buffer allocated is big enough.

    > if ( col6x == col6 )
    Lookup strcmp()
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
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  4. #4
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    Thanks Salem, I get what you mean. Once I'm done will post the working code. Thanks a lot!

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