Thread: About char pointer to char array

Hi All,

I have used openssl rsa encrypt function, and the result is in
'unsigned char'. I have tried to display it and check the values, and it also get the expected result.

Code:

for(int i=0; i<128; i++)
{
     printf("0x%02X, ", *out);
}

Result=
0x29, 0x4F, 0xD6, 0xD6, 0x6D, 0x6C, 0x36, 0x41, 0x19, 0xD7, 0x3E, 0x07, 0xCD, 0xCE, 0x70, 0xAB, 0x2D, 0xBA, 0x90, 0x0E, 0x33, 0x24, 0x5B, 0xAF, 0x52, 0x62, 0xF8, 0x9A, 0x65, 0x5B, 0x1D, 0x96, 0x6B, 0x8F, 0x3A, 0xC3, 0xDC, 0x15, 0x79, 0xE0, 0x7B, 0x6D, 0x7B, 0xD8, 0x0E, 0x67, 0x72, 0x7C, 0x09, 0x9C, 0xBB, 0x74, 0xCE, 0x24, 0xBA, 0xAF, 0x06, 0x78, 0x42, 0x04, 0xEB, 0x02, 0x70, 0x7F, 0x0A, 0x8E, 0x55, 0xDD, 0x1C, 0x27, 0x82, 0x15, 0x03, 0xB5, 0xF9, 0xE9, 0x2F, 0x64, 0x65, 0x45, 0x58, 0x89, 0xDB, 0xC3, 0xB9, 0x54, 0xFE, 0xBD, 0x18, 0x7D, 0x70, 0x60, 0x51, 0x1B, 0x86, 0xBB, 0x9F, 0x12, 0x0D, 0xF1, 0x88, 0xDD, 0x31, 0xDA, 0x0F, 0xF1, 0x0D, 0x8F, 0x46, 0x7B, 0x53, 0x86, 0xA7, 0xBB, 0x6F, 0xFE, 0x43, 0xD3, 0x04, 0xF2, 0xA0, 0x6C, 0x85, 0x08, 0xCE, 0x27, 0xDA, 0x0C,
================================================
how can I change this unsigned char to unsigned char array
for e.g

out2[0]='2'
out2[1]='9'
out2[2]='4'
out2[3]='F'
.
.
.
out2[254]='0'
out2[255]='C'

What you have shown so far indicates that "out" is a pointer. If it points to a block of memory that is 128 bytes long you can use array subscript on it directly, no need to convert. But there may be additional things here that you have not shown because the result of the code should produce 128 identical numbers since you never update out.

Oh, I have passed the char arrary to the RSA function, and the return is that:

out[0]= 41
out[1]= 79
....
that's mean each of the char array store the oct number; therefore, when I printf("%02x", out[0]), the value is 29.
can anyone tell me how to change it in hex and store in char array.

Originally Posted by homoon

Oh, I have passed the char arrary to the RSA function, and the return is that:

out[0]= 41
out[1]= 79
....
that's mean each of the char array store the oct number; therefore, when I printf("%02x", out[0]), the value is 29.
can anyone tell me how to change it in hex and store in char array.

That is not an octal number, 41 in decimal is 29 in hex. You don't need to worry about it, octal, decimal or hex is all stored with the same representation, it's a matter of presentation only. Try this for example:

Code:

int a = 41;

printf("%d\n", a);
printf("%x\n", a);
printf("%o\n", a);