Thread: Calculation error

Code:

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

void main(void)
{
    //declaration
    float x, y, distance, slope;

    //intialization
    printf("Enter the co-ordinates of point P (X , Y): ");
    scanf("%f %f", &x, &y);
    printf("\nThe point is ( %f , %f )", x, y);

    //calculation
    
    slope = y / x;
    distance = sqrt( x * x + y * y);
    

    if ( x = 0 )
    {
        printf("The slope is infinity!"); 
        printf("The distance is %.2f", distance);
    }

    else
    {
        printf("\nThe slope is %.2f and the distance is %.2f",slope, distance);

    }
    exit( 0 );

} /* end main program */

Problem with the infinity part , the output shows 1.#J for some reason and I don't understand which part went wrong.

If X and Y are both numbers , the program seems to be working fine but if X = 0 , the problem just shows the slope output to be 1.#J instead of showing " The slope is infinity"

You calculate slope before you check if x is 0. You should not be dividing by 0. You should only be calculating the slope after you've verified that x is not 0. This:

Code:

//calculation
     
slope = y / x;
distance = sqrt( x * x + y * y);
     
 
if ( x == 0 )
{
    printf("The slope is infinity!");
    printf("The distance is %.2f", distance);
}
else
{
    printf("\nThe slope is %.2f and the distance is %.2f",slope, distance);
}

Should be this:

Code:

//calculation
     
distance = sqrt( x * x + y * y);
     
if ( x == 0 )
{
    printf("The slope is infinity!");
    printf("The distance is %.2f", distance);
}
else
{
    slope = y / x;
    printf("\nThe slope is %.2f and the distance is %.2f",slope, distance);
}

Originally Posted by Kazansky

Remember "=" is for assignment, it's setting 'x' to zero, == is for comparisons.

As a corollary to this: COMPILE WITH WARNINGS ENABLED, and the compiler would have TOLD you this before it even finished compiling.