Code:#include<stdio.h> #include<stdlib.h> int main(void) { unsigned number1, number2; char aString = "5.55"; /* ?????????????????????????????? */ printf("%d.%d\n", number1, number2); return EXIT_SUCCESS; }
How can i assign 5 to number1, 55 to number2.
So that the printf will print out 5.55?
Please help. Thanks!
Well assuming that you really need to extract the decimal part and the integer part you could use strtok() to break up the string based on the location of the '.', then use strtol() to transform the parts in numbers.
Alternatively, you could just convert it directly to a floating point number using strtof().
In any case, you need to Google these functions and read the examples.
1. Get rid of gets(). Never ever ever use it again. Replace it with fgets() and use that instead.
2. Get rid of void main and replace it with int main(void) and return 0 at the end of the function.
3. Get rid of conio.h and other antiquated DOS crap headers.
4. Don't cast the return value of malloc, even if you always always always make sure that stdlib.h is included.
There are a couple of ways to do that
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Code:#include<stdio.h> int main(void) { char aString[]="15.55"; char *res,*tok="."; long int ar[5]; unsigned long int number1,number2; int i=0; res=strtok(aString,tok); while(res!=NULL) { ar[i++]=atol(res); res=strtok(NULL,tok); } number1=ar[0]; number2=ar[1]; printf("%ld %ld",number1,number2); return 0; }
Please don't provide entire solutions to people asking for help, it is completely counterproductive to their learning.
1. Get rid of gets(). Never ever ever use it again. Replace it with fgets() and use that instead.
2. Get rid of void main and replace it with int main(void) and return 0 at the end of the function.
3. Get rid of conio.h and other antiquated DOS crap headers.
4. Don't cast the return value of malloc, even if you always always always make sure that stdlib.h is included.
sry...i din know that
anyway, thanks for helping!
