command line args problem

I have a problem checking on the command line args.

Code:

int main(int argc, char* argv[])
{
printf("%s",argv[1]);
if (argv[1]=="hello")
 printf("works!");
return 0;
}

But for some reason the "if" doesn't pass. Eventhough it does prints out what the "if" states.

Why is that?

What do you mean the "if doesn't pass". What does this program output?

You should be using the strcmp() function to compare your strings, not the comparison operator==.

Jim

You need to use strcmp to compare strings in C. As it stands, your equality test is trying to compare the address of argv[1] with the address of the string literal "hello". These two addresses will NEVER be the same.

Ahah, got it. Thanks.

You should check argc to ensure you're being passed enough arguments before you start using argv[1]!
Also you should indent your code and use curly braces for the if statement.