Hi guys I'm wondering why I use * before define a function ?
For example
Code:
char *strcopy(char *copy,char *original) { /* Why ı can not use just strcopy instead of *strcopy????*/ for(int k=0;(*copy++ = *original++)!='\0';) k++; return copy ; }
ıs there anyone who can help me please ?
Last edited by dayanike; 04-24-2012 at 09:15 AM.
We would if we could see the code you are referring to.
1. Get rid of gets(). Never ever ever use it again. Replace it with fgets() and use that instead.
2. Get rid of void main and replace it with int main(void) and return 0 at the end of the function.
3. Get rid of conio.h and other antiquated DOS crap headers.
4. Don't cast the return value of malloc, even if you always always always make sure that stdlib.h is included.
Sorry I've just edited it .
Ahh, the little '*' there belongs to the return value not to the function name. Unfortunately the following is equivalent in C:
char* myFunc(void)
AND
char *myFunc(void)
hence your little confusion.
1. Get rid of gets(). Never ever ever use it again. Replace it with fgets() and use that instead.
2. Get rid of void main and replace it with int main(void) and return 0 at the end of the function.
3. Get rid of conio.h and other antiquated DOS crap headers.
4. Don't cast the return value of malloc, even if you always always always make sure that stdlib.h is included.
thanks a lot for your quick answer
