intCode:#include <stdio.h> int f(int* a, int* b); int main() { int a = 6, b = 7, c = 8; b = f(&c, &a); printf("a = %d, b = %d, c = %d\n", a, b, c); return 0; } int f(int* a, int* b) { *a = *a + *b; *b = *a - *b; printf("a = %d, b = %d\n", *a, *b); return 3*(*b); }
How about you read your previous thread again, and then post what YOU think is happening.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
I got everything working right I just dont know how c=14 if theres no equation or anything given for it?
But there is. c is not modified in main, it's modified in f(). Remember, the address of c is passed as the first parameter to f().
Ahhh gotcha. Thanks
