Thread: Error in a decimal to bcd conversion problem

I have written a program to input a decimal number and convert it to a bcd. I have been able to remove the bugs, but my program is returning a random value upon entering the input. For example, if I enter 3 as the input it gives me 0 4210704 instead of 011. Kindly help me out, I think there is some problem with regards to returning the value of a variable in the array. Below is my program:

Code:

#include<math.h>
#include<stdio.h>
#include<stdlib.h>
int *dectobin(int dig);
int main()
{
    int n,dig,i=0;
    int bcd[100]={0},b;
    printf("Enter the number to be converted into BCD");
    scanf("%d",&n);
    while(n!=0)
               {
               dig=n%10;
               n=n/10;
               b=dectobin(dig);
               bcd[i]=b;
               i=i+1;
               }          
    for(;i>=0;i--)
               {
               printf("%d\t",bcd[i]);    
               }
    system("pause");
    return 0;
}
int *dectobin(int dig)
{
    int r,i=0,j=0;
    int array[100]={0};
    static int reversearray[100]={0};
    while(dig!=0)
    {
    array[i]=dig%2;
    dig=dig/2;
    i=i+1;
    }
    for(;i>=0;i--)
    {
         reversearray[j]=array[i];
         j+=1;
    }
    return reversearray;
}

Doesn't your compiler display any warning at this line?

Code:

b=dectobin(dig);

It's totally wrong because you are assigning pointer to value.