Thread: How to print number of characters per line

I dont have any idea about my assignment,a pseudo code or even better,part of the code,will help me a lot~
Well,my program should ask the user to enter a paragraph of words,then output the words according to 20 char per line.Also the end of the line cant be half of the word.I cant explain it quite well,but the example below shows what i should do.

Enter some sentences (between 150 ¨C 200 chars): What¡¯s the
difference between a mathematician and a computer scientist?
Answer: A mathematician has all the theories and no answers. A
computer scientist has all the answers and no theories.


Formatted text:
What's the difference between
a mathematician and a computer
scientist? Answer : A
mathematician has all the
theories and no answers. A
computer scientist has all the
answers and no theories.

oops,sorry~i left out one part,all last letter cant be spaces,so it means that the spaces left should be devided amongly between the line.

But I cant figure it out,and i just wan some pseudo code or the algorithm how to do it so that I know where to start.

first,I read in the paragraph,then use a string tokenizer to tokenize every words with a blank space.
second,I make every token an array of char.(But I get weird symbol while doing this,and not sure if i can do it so.)
third,i loop through every array and count the number of char in it(make sure it doesn't exceed the number).
then count the array that i have,and printf with %(number_per_line/array_count) .

Code:

#include <stdlib.h>
#include <string.h>


#define SIZE 200
#define number 150
#define perline 5


int main(void)
{
    char para[SIZE]="Where there is will there is a way.";
    char *ch;
    int i=0;
    char *word[10];
    ch=strtok(para," ");
    while(ch!=NULL)
    {
        word[i]=&ch;
        ch=strtok(NULL," ");
        printf("%c",*word[i]);
    }
    return 0;
}

well,almost done part3,but cant printf the words and program crash.

Code:

#include <stdlib.h>
#include <string.h>


#define SIZE 200
#define number 150
#define perline 5




int main(void)
{
   char para[SIZE]="Where there is will there is a way.";
    char *ch;
    int i;
    int x=0;
    char *word[10];
    ch=strtok(para," ");
    while(ch!=NULL)
    {
        word[i]=ch;
        ch=strtok(NULL," ");
        printf("%c\n",word[i]);
    }
    for(i=0;i<10;i++)
    {
        if(x+strlen(word[i])<=perline)
        {
            x+=strlen(word[i]);
            printf("%c",*word[i]);
        }
        else
        {
            printf("\n");
            x=0;
            printf("%c",*word[i]);
        }
    }


    return 0;


}

ok,now i just need to optimised my code,so that blank spaces wont appear in the last place.For this part of code:

Code:

for(i=0;i<10;i++)

is there a way to know how many token are being created or if word[i] exist,rather than hardcoding i<10?