Thread: I Cannot GET THIS TO WORK.. (Saving A STRING Into An Array...)

All I want to do is ask the user to enter words, then I bubble sort them alphabetically, then print them back out. THE PROBLEM IS.. When I try to store "str" into the words array, idk what's happening... When I print them out, it's only saving the LAST word I typed into every array location..

Code:

#include "stdafx.h"
#include <stdio.h>
#include <string.h>


#define MAXLENGTH 15
#define MAXWORDS 3


int _tmain(int argc, _TCHAR* argv[])
{


char str[80];
char *words[25];
char *hold;
int j;
int i;
int wordcount=0;


while (wordcount<MAXWORDS){


	  printf("Enter a word: ");
		 fgets(str, MAXLENGTH, stdin);


  /* remove newline, if present */
  i = strlen(str)-1;
  if( str[i] == '\n') 
      str[i] = '\0';


  printf("%s\n",str);


  words[wordcount]=str;


	wordcount++;


}


printf("%d words.\n",wordcount);


for(i=1;i<wordcount;++i)
	for(j=wordcount-1;j>=i;--j)
		if (strcmp(words[j-1],words[j])>0){
		hold=words[j-1];
		words[j-1]=words[j];
		words[j]=hold;
		}




for(i=0;i<wordcount;i++)
	printf("%s \n",words[i]);


	return 0;
}

I realize "char*s are not strings. They are pointers"

But how do I fix this?

All I want to do is ask the user to enter strings 1 line at a time, and have them saved in an array.

Then sort the strings alphabetically in the array.

Then print it.

That's all!!.. I have the sorting working, I just don't have the storing the strings from the user into the array!

I always thought char array[10][10]; was the same as char* array[10]; Are not the brackets just a dereference such as the '*'?