Help with formatting text

This is a discussion on Help with formatting text within the C Programming forums, part of the General Programming Boards category; Code: void formattingText() { int maxNoChars; char inputSentence[maxFormattingTextSize]; printf("Formatting Text\n"); printf("-------------------------\n\n"); printf("Enter an integer (maximal no of chars per line) ...

  1. #1
    C89
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    Help with formatting text

    Code:
    void formattingText()
    {
        int maxNoChars;
        char inputSentence[maxFormattingTextSize];
            
        printf("Formatting Text\n");
        printf("-------------------------\n\n");
        printf("Enter an integer (maximal no of chars per line) :\n");
        
        scanf("%d", &maxNoChars)/
        printf("Enter some sentences (between 150 - 200 chars) :\n\n");
        inputSentence == fgets(inputSentence,maxFormattingTextSize,stdin);
    inputSentence == fgets(inputSentence,maxFormattingTextSize,stdin);
        /*gets(inputSentence);*/
        printf("Formatted text:\n");
        /*printf("%5d", inputSentence);*/
        printf("%s", inputSentence);
        
        
    }
    What do I have to add to this code to restrict the maximum number of characters per line? Any help would be appreciated.

  2. #2
    Registered User TheBigH's Avatar
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    What exactly are you trying to do? Do you want to chop the end off lines that are too long?

    Also, lines 13 and 12 are the same. And you don't use == to assign values. The == is for checking equality. Use a single = instead.
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    while(!asleep) {
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  3. #3
    C++ Witch laserlight's Avatar
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    You could set maxFormattingTextSize and stop pointlessly comparing the return value of fgets to inputSentence.
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  4. #4
    C89
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    Whoops, thanks xD

    Yeah I want to set the maximum width of the block of text to the integer the user inputs. So if it's say 20:

    This :
    Hello this is a sample paragraph well I'll just type some more words

    Will become something like this:

    Hello this is a samp
    le paragraph well I'
    ll just type some m
    ore words

  5. #5
    - - - - - - - - oogabooga's Avatar
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    Change the slash after the scanf to a semicolon.
    Get rid of the repeated fgets statement.
    Get rid of the inputSentence == part.
    Then post your attempt to do the assignment.
    The cost of software maintenance increases with the square of the programmer's creativity. - Robert D. Bliss

  6. #6
    C89
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    Code:
    void formattingText()
    {
        int maxNoChars;
        char inputSentence[maxFormattingTextSize];
            
        printf("Formatting Text\n");
        printf("-------------------------\n\n");
        printf("Enter an integer (maximal no of chars per line) :\n");
        
        scanf("%d", &maxNoChars);
        printf("Enter some sentences (between 150 - 200 chars) :\n\n");
        inputSentence == fgets(inputSentence,maxFormattingTextSize,stdin);
        
        printf("Formatted text:\n");
        printf("%s", inputSentence);
        
    }
    There's my weird typos fixed and now I'll try and solve this. Do I need to somehow put the int next to the s in "%s"? I don't really understand.

  7. #7
    Registered User TheBigH's Avatar
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    You don't need the inputSentence == part, like oogabooga said.
    Code:
    while(!asleep) {
       sheep++;
    }

  8. #8
    C++ Witch laserlight's Avatar
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    Quote Originally Posted by C89
    Yeah I want to set the maximum width of the block of text to the integer the user inputs. So if it's say 20
    Oh. That is something of a chicken and egg scenario: you need to know what the user has entered in order to size the array to accommodate exactly that, but you need to have an array in order to read what the user has entered. Variable length arrays won't quite help here since you cannot resize them (i.e., they are variable length at compile time, but once created at run time, the length is fixed).

    However, I note that this function is about formatting text, according to the name. Perhaps you really should be giving it parameters for the string to be formatted, and then you limit the output to the given max number of characters., rather than the input.
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  9. #9
    C89
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    Code:
    void formattingText()
    {
        int maxNoChars;
        char inputSentence[maxFormattingTextSize];
            
        printf("Formatting Text\n");
        printf("-------------------------\n\n");
        printf("Enter an integer (maximal no of chars per line) :\n");
        
        scanf("%d", &maxNoChars);
        printf("Enter some sentences (between 150 - 200 chars) :\n\n");
        gets(inputSentence);
        
        printf("Formatted text:\n");
        printf("%s", inputSentence);
        
    }

  10. #10
    C89
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    Quote Originally Posted by laserlight View Post
    Oh. That is something of a chicken and egg scenario: you need to know what the user has entered in order to size the array to accommodate exactly that, but you need to have an array in order to read what the user has entered. Variable length arrays won't quite help here since you cannot resize them (i.e., they are variable length at compile time, but once created at run time, the length is fixed).

    However, I note that this function is about formatting text, according to the name. Perhaps you really should be giving it parameters for the string to be formatted, and then you limit the output to the given max number of characters., rather than the input.
    Ok, I understand conceptually what I have to do now but I am unsure of the syntax I will require. Thank you for your time.

  11. #11
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    Quote Originally Posted by C89 View Post

    Do I need to somehow put the int next to the s in "%s"?
    You would need something like "%.20s"!!! But since this 20chars per line is not fixed every time and you can't use any variable (maxNoChars) in the formatting string you need to think otherwise. Like, printing char by char till you print maxNoChars per line or you have already printed all the chars.

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