# Thread: need help with a formula!!

1. ## need help with a formula!!

this is what i need to do:
insert width and length of a rectangular.
how many squares of 20 cms side can u put inside that rectangular.
and whats the area left with no squares.

with the width and lenght of the rectangular i can calculate the area of the rectangle.
Using the area i can calculate how many 20x20 is inside that area. but if its a 30x35 rectangle A=950, and 20x20 is 400. it says it can hold 2 squares ( 400x 2 =800 < 950) , but its not true it can only hold 1 and some area is left over.

How do i have to write to be sure that it reads the square as a 20x20 and not just an area of 400?

2. It's a tougher algorithm than you are trying to make it. I believe you are going to need to do it on a row by row basis. Basically check whether the rectangle has a height of at least 20, if it does, fill that row with as many 20 x 20's as you can. Then subtract 20 from the overall rectangle height, and test it again. Keep a count of how many 20 x 20s you have used and then subtract that from the original rectangle area. I don't want to do you're hw for you, but I think this is the correct alg. Although you could make it more efficient, by just caching the first number of 20x20s that fit into a row and then figuring out how many rows you can fit into the rectangle. Good luck.

3. Use division on both user entered lengths... the answer is the result of those values multiplied by each other.

4. That's true and much better approach than mine. % is your friend.

5. Yeah thx, already fixed it