Comparing string to arry of strings

Hello there,

I'm new to C programming and I have the following exercise to do:

"Consider an array v[0, 1,..., (n-1)] whose elements are strings. Remember that, in C a string is just an array of chars ending with the null character '\0'. So, you can suppose that v was declared this way: char *v[n]. Write a function that receives a string x and returns a index j in which x = v[j]. If this j doesn't exist, the function must return -1."

Here's what I did:

Code:

#include <stdio.h>
#include <string.h>

int contem(char string, char *v, int n) {

    int i;

    for (i = 0; i < 10; i++) {
        if (strcmp(v[i], string) == 0) {
            return i;
        }
    }

    return -1;

}

main() {

    char *v[10];
    v[0] = "File";
    v[1] = "Edit";
    v[2] = "View";
    v[3] = "Search";
    v[4] = "Tools";
    v[5] = "Documents";
    v[6] = "Help";
    v[7] = "Open";
    v[8] = "Save";
    v[9] = "Undo";
    
    char string [100];

    printf("String to search for: ");
    gets(string);

    int ret = contem(string, v, 10);

    if (ret == -1) {
            printf("The string is not in the array.");
            return 0;
    }

    else printf("The string is at position: ", ret);

    return 0;

}

I get the following warnings:

warning: passing argument 1 of 'strcmp' makes pointer from integer without a cast

warning: passing argument 2 of 'strcmp' makes pointer from integer without a cast

warning: passing argument 1 of 'contem' makes integer from pointer without a cast

warning: passing argument 2 of 'contem' from incompatible pointer type


What am I doing wrong? Does the array v must really be declared as a pointer?

Thanks in advance.

Regards,
Samir

What is the type of v[i]? What is the types of the parameters of strcmp?

It needs to be declared as an array of pointers (for that is what you're passing).

int contem(char string, char *v[], int n)

v is declared like this:
char *v[10];

After I have added the [] to the second argument of the contem function I got only two warnings:
warning: passing argument 2 of 'strcmp' makes pointer from integer without a cast

warning: passing argument 1 of 'contem' makes integer from pointer without a cast

Is it that I am comparing a pointer to a char?

Originally Posted by Samir Aguiar

Is it that I am comparing a pointer to a char?

Yes indeed! Check what parameter types strcmp takes and then check what you're passing into it. Also the first parameter you're passing into contem() isn't right.
Lastly, don't use gets() !

Now I get it. v is declared as an array of pointers to char (char * v[]) while string is declared as an array of chars. I was passing to function contem v as a pointer to char and string as a char.
I have changed contem arguments to this:

int contem(char string[], char * v[], int n);

And it solved the problem. Thanks for the help guys, I appreciate it!