Thread: How does this not work?!

I am under the impression that one can declare a pointer, list, and assign to it values as if it were an array. I attempted to do so, and got the error: lvalue required as left operand of assignment.

Code:

int main()
{
   int* list;
   int a=2, b=3;
   list = &a;
   (list + 1)= &b; /* why does this not work? */
   return 0;
}

The closest thing I can make to your example would be:

Code:

int *list[2];
int a = 2, b = 3;

*list = &a;
*(list + 1) = &b;

Notice that I had to declare an array of 2 elements.