problem while printing unsigned long long int

Hello,

When I try to print an unsigned long long int I get a different number displayed.
This is the code I'm using:

Code:

int main(int argc, char *argv[]) {

    printf ( "ULLONG_MAX: %llu\n", ULLONG_MAX );
    unsigned long long int power=atoi(argv[1]);
    unsigned long long int shift_power=0;

    printf("normal, %llu\n", power);
    shift_power=power<<10;
    printf("after shift, %llu\n", shift_power);
...

running it with:
> ./test 35184372088832

the result is:

ULLONG_MAX: 18446744073709551615
normal, 0
after shift, 0

Any idea please? do you know why I'm getting 0 for both?
thx in advance

What is your compiler and OS? On Windows, you may need a different format specifier, i.e., %I64u instead of the standard %llu. Also, you should be using strtoull for the conversion.

Hi

thx for reply. You're right atoi converts to integer !!
My OS is Redhat 6 and I use gcc. I changed my code by using strtoull instead of atoi and now is better but not perfectly fine:

Code:

unsigned long long int power=strtoull(argv[1], NULL, 16);

In this case I get a different number like:
> ./test 35184372088832
got back

normal, 1913161778
after shift, 1959077660672

Hello

solved!
actually I forgot to include the stdlib.
Moreover the int base is 10 and not 16 as I wrote

thx for the tip