Thread: Convert string to ASCII values

So something like this:

Code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main (void)
{
    char string[50];
    int i, sum;
    scanf("%s", string);
    sum = 0;
    for(i = 0; i < strlen(string); i++)
        sum += (int)string[i];

    printf("(%d)\n", sum);
    system("pause");
    return 0;
}

Right. There's no sprintf in there, hence oogabooga's confusion and question. You're 99% of the way there. You already add up the ASCII values. The only thing you're missing is the modulo: sum % some_size.

My bad, the sprintf is for the second hashing function where we have to write the ASCII values to a string.

To complete this though:

Code:

#include <stdio.h> 
#include <stdlib.h> 
#include <string.h>

#define SIZE 10  
int main (void) 
{     
    char string[50];     
    int i, sum, address;     
    scanf("%s", string);     
    sum = 0;     
    for(i = 0; i < strlen(string); i++)         
        sum += (int)string[i];

    address = sum % SIZE;     
    printf("(%d)(%d)\n", sum, address);     
    system("pause");     
    return 0; 
}

The size is predetermined for our assignment. In this case, we are using 10 to test our collision resolution method

That looks good. A couple of points:
1. You could use a format of "%49s" in your scanf to protect from possible buffer overflow. And note that %s (with or without the size limit) will not read in a string with a space in it, but that may be the behavior you want.
2. It might be better to cast to unsigned char instead of int for the summation since, if chars are signed (and they may or may not be!), summing them (casted to int or not) will actually subtract ... however that may be the behavior you want. I suppose it doesn't matter as long as you're consistent.