Turing to C Programming

I have to change this code from Turing to C language but I'm not sure how.

Code:

var a : array 1 .. 10 of intvar n, x, sum, offer : int
var avg : real


a (1) := 100
a (2) := 500
a (3) := 1000
a (4) := 5000
a (5) := 10000
a (6) := 25000
a (7) := 50000
a (8) := 100000
a (9) := 500000
a (10) := 1000000


get n
for i : 1 .. n
    get x
    a (x) := 0
end for
sum := 0
for i : 1 .. 10
    sum := sum + a (i)
end for
avg := sum / (10 - n)
get offer
if offer > avg then
    put "deal"
else
    put "no deal"
end if

I can easily translate most of the program except for this part. I know its a loop, but how would you change this? :

Code:

get n
for i : 1 .. n
    get x
    a (x) := 0
end for
sum := 0
for i : 1 .. 10
    sum := sum + a (i)
end for
avg := sum / (10 - n)

Help please?

EDIT: Alright I somewhat figured this. The first loop is to check how many inputs are left. There are 11 inputs available in total. For ex, if a user enter 2 in the beginning, there are 10 inputs left to be taken from the user. Is there a way to program this command using a loop?

Just look at a normal for loop:

Code:

for (initialization; condition; increment) {
    statements;
}

No but what I don't understand is where "i" came from, and the semi colon, along with ".."


Sorry, I am somewhat a beginner at this

I'm not familiar with the language, but I'm guessing it's one of these situations:

Code:

#include <stdint.h>

/* ... */

uint8_t i;

for (i = 0; i < 5; i++) {
    /* your stuff */
}