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may i know what is wrong with this coding? tq

This is a discussion on may i know what is wrong with this coding? tq within the C Programming forums, part of the General Programming Boards category; Code: Start(){ char exit,key; exit =1; while(exit) { key = if ((key & 0x40)==0) exit=0; } }...

  1. #1
    Registered User
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    Jan 2012
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    may i know what is wrong with this coding? tq

    Code:
    Start(){
    
    
    char exit,key;
    
    
    exit =1;
    
    
     while(exit)
          {
    
    
     key =
    
    
    if ((key & 0x40)==0) exit=0;
    
    
    }
    
    
    }

  2. #2
    C++ Witch laserlight's Avatar
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    It has syntax errors.
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

  3. #3
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    exit can't be a variable name since it is similar to return.

  4. #4
    a_capitalist_story
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    It's incomplete.

  5. #5
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    Code:
    
    
    Start(){ /* what does it return? compiler should warn */ char exit,key; exit =1; while(exit) { key = /* key equals what now? */ if ((key & 0x40)==0) exit=0; /* don't waste time doing a flag */ } } /* horrible indentation all the way through */


    It should look something like this:

    Code:
    void Start (char key)
    {
        while (!(key & 0x40))
            key;    /* idk. key++? key--? key*=5? you need to specify */
    }

  6. #6
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    That has to be the ugliest code I've ever seen.

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