returning an array of int

[JonathanS]

Before I had problems passing an int array, now it is returning it...

Areas of importance is the last function "int* ReadPrices(void)" and lien 25.

Thanks!

data.dat is:

5 10 15 20 25 30 35 40 45 50 55 60 65 70 75

My code is:

#include <stdio.h>
#include <stdlib.h>

void seatChart (int AvailableSeats[15][20]);
int* ReadPrices(void);

int main()
{


    int choice;

    int row;
    int seat;

    int i;

    int AvailableSeats[15][20] = {0}; //seats[row][seat]

    int ticketsSold = 0;

    int sale;
    int PriceList[16];

    PriceList = ReadPrices();


    for(;;)
    {
        seatChart(AvailableSeats);

        printf("\n\nMenu:");
        printf("\n1) Buy ticket");
        printf("\n2) Total sell and exit");
        printf("\n\nEnter your choice : ");
        scanf("%d", &choice);

        if (choice == 1)
        {
            printf("\n\nEnter row: ");
            scanf("%d", &row);

            printf("\nEnter seat: ");
            scanf("%d", &seat);



            if (row<0 || row >14 || seat<0 || seat>19)
            {
                printf("Invalid seat choice");
            }

            else if(AvailableSeats[row][seat] == 0)
            {

                AvailableSeats[row][seat] = 1;
                ticketsSold++;
                sale = sale + PriceList[row];
            }


            else
            {
                printf("\nSeat is already taken");
            }




            continue;
        }



        if(choice == 2)
        {
            printf("\n\nTOTAL TICKETS SOLD: %d", ticketsSold);
            printf("\nTOTAL REVENUE: Y");
            break;
        }

        printf("Invalid choice");
        ticketsSold--;

    }


    return 0;
}

void seatChart (int AvailableSeats[15][20])
{
    int i;
    int o;

    printf("\n* Seats available");
    printf("\n# Reserved Seats");
    printf("\nSeats:  0  1  2  3  4  5  6  7  8  9 10 11 12 13 14 15 16 17 18 19");



    for(o = 0; o<=14; o++)
    {
        printf("\nRow %2d", o);

        for(i = 0; i<=19; i++)
        {

            if(AvailableSeats[o][i] == 1)
            {
                printf("  #");
            }

            else
            {
                printf("  *");
            }
        }
    }

}

int* ReadPrices(void)
{
    int i;
    int tempPriceList[16];

    FILE* fts;
    fts = fopen("data.dat", "r");

    for(i = 0;i<=14;i++)
    {
        fscanf(fts, "%d ", &tempPriceList[i]);
    }

    for(i=0;i<=14;i++)
    printf("%d ", tempPriceList[i]);

    return tempPriceList;
}

[laserlight]

Get the caller to pass a pointer to the first element of the array, then modify the array through that pointer. What you are doing now is returning a pointer to the first element of an array that is about to be destroyed as it goes out of scope.

[mnd22]

Also take note that on line 25 you are trying to change the address of the array which will not work, think about array as a constant pointer you cannot modify it. Do what laserlight suggested pass the array as a function parameter.

[camel-man]

Why return an array? Doesnt the function change the original in main?