If else if stament help

**langamer101** · 01-18-2012

ArunS
I run program then I input x=10,y=5,z=15
output = 10
hmmmm double digits and single digit numbers do not work.
it seems that i was so happy with the program working with 1 digit xyz 2digits xyz but not 1 and 2 digits xyz.

**ArunS** · 01-18-2012

Originally Posted by langamer101

ArunS
I run program then I input x=10,y=5,z=15
output = 10
hmmmm double digits and single digit numbers do not work.
it seems that i was so happy with the program working with 1 digit xyz 2digits xyz but not 1 and 2 digits xyz.

Its not a matter of either single digit or double digit?
Ok! Try to check for the following inputs.
i/p: x=5; y=4; z=6;

**Tibo-88** · 01-18-2012

It is not a problem about single digit or double digit, it is just about the code logic. Again, what you want to check in your if and if else statement is for example x > y AND x > z which is the logic translation for testing "is x bigger than y and bigger than z?". Try to use that condition in your code for each if and if else, and you'll see that it should work.

**ArunS** · 01-18-2012

Originally Posted by langamer101

Its looks exactly the same but its not in logic.
so basically i started looking where would the large number go if true or false
if x > y it would print x if false goes to next else if
if z > y it would print z if false goes to next else if
if y > x it would print y if false goes to x. but thats how I solved it.
the program now works.

if x > y it would print x if false goes to next else if
you are printing x value even if z is greater the x.
you have to print the value of x only if it is greater than both y and z.

**langamer101** · 01-18-2012

omg, what sorcery it this.
output is 5??????????????????????

**ArunS** · 01-18-2012

Originally Posted by langamer101

omg, what sorcery it this.
output is 5??????????????????????

Use logical operator, as per post#18

**langamer101** · 01-18-2012

lol that was all. x>y>z on the first if
OH I SEE. omg I look so ..............
thanks guys.
edit
more problems...............omg ill try to figure it out.

**ArunS** · 01-18-2012

we have concentrated only for x, you have to do it in a same way for y and z conditions, thats all.

**langamer101** · 01-18-2012

it this code correct now?. I run it, put aruns x=10,y=5,z=15 and x=5,y=4,z=6 and works.

Code:

#include<stdio.h>
#include<conio.h>
main()
{
    clrscr();
    int x,y,z,l;
    printf("Enter value for x: ");
    scanf("%d",&x);
    printf("Enter value for y: ");
    scanf("%d",&y);
    printf("Enter value for z: ");
    scanf("%d",&z);
    if (x>y>z)
        printf("The large number is %d", x);
    else if (z>y)
        printf("The large number is %d", z);
    else if (y>x)
        printf("The large number is %d", y);
    else if (x>z)
        printf("The large number is %d", x);


    else
        printf("all values are the same");
        getch();
        return(0);
}

**Tibo-88** · 01-18-2012

First, I did not notice from the beginning, but take some time to read this page.

Then "x>y>z" is not good, that is not the proper way to do it. You have to compare if x>y AND x>z, by using the AND logic operator, which is "&&" in C.

Also, as ArunS mentioned, you have to apply this logic for all of the other statement.

At that point, and without trying to be mean, I think following a C tutorial would be a good idea for you. You will then understand much better about the theory and the syntax of the C language, and you will be able to solve this kind of problems in 5 minutes.

**langamer101** · 01-18-2012

ummm, hmm, thanks.
time to start reading and quiz myself on C tutorial.

**ArunS** · 01-18-2012

Originally Posted by langamer101

it this code correct now?. I run it, put aruns x=10,y=5,z=15 and x=5,y=4,z=6 and works.

Code:

#include<stdio.h>
#include<conio.h>
main()
{
    clrscr();
    int x,y,z,l;
    printf("Enter value for x: ");
    scanf("%d",&x);
    printf("Enter value for y: ");
    scanf("%d",&y);
    printf("Enter value for z: ");
    scanf("%d",&z);
    if (x>y>z)
        printf("The large number is %d", x);
    else if (z>y)
        printf("The large number is %d", z);
    else if (y>x)
        printf("The large number is %d", y);
    else if (x>z)
        printf("The large number is %d", x);


    else
        printf("all values are the same");
        getch();
        return(0);
}

Why don't you consider with logical operators for your implementation?

**langamer101** · 01-18-2012

my teacher has not taught me about "&&, ||, !" logical operators yet.
only these ">,<,=,==,>=,<=" relational operators.

**Tibo-88** · 01-18-2012

It is actually possible to make it without the "&&", but then the logic will be different.

I usually don't like to give so detailed answer, but you seem like you thought quite a lot, so I will make an exception

.

Here is what you could do :

-Assign the x value to l.
-Test if l is lesser than y.
-If yes

-Assign the y value to l.
-Test if l is lesser than z.
-If yes, then z is the biggest.
-If no y is the bigest.

-If no ...

I think you can find the rest by yourself.

**langamer101** · 01-18-2012

here is code now with && logical operator

Code:

#include<stdio.h>
#include<conio.h>
main()
{
	clrscr();
	int x,y,z,l;
	printf("Enter value for x: ");
	scanf("%d",&x);
	printf("Enter value for y: ");
	scanf("%d",&y);
	printf("Enter value for z: ");
	scanf("%d",&z);
	if (x>y && x>z)
		printf("The large number is %d", x);
	else if (z>y && z>x)
		printf("The large number is %d", z);
	else if (y>x && y>z)
		printf("The large number is %d", y);
	else
		printf("all values are the same");
		getch();
		return(0);
}

tibo Ill try this x value to l and so on what you posted

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