Thread: Basic C programming help

I cannot seem to figure out why this will not work!?

http://i.imgur.com/PuYO8.png

That is the code as you can see everything is ok and all should be working fine.

http://i.imgur.com/gnr4v.png

Now you can see i enter 111 into the stdin, this should be represented in the next picture as 111.

http://i.imgur.com/Xj62h.png

But as you can see that's not the case, for whatever reason num4 ALWAYS prints itself even when the if conditions are against it. When i delete num4 completely from the code everything works as per usual. Am i doing something wrong?? cos the code all looks identical and should be working fine surely?? Sorry i don't know much about C programming :/

Am i doing something wrong??

Yes. You're posting pictures of your code instead of your code.

Code:

#include <stdio.h>
 
int main( void )
{
   int num1;
   int num2;
   int num3;
   int num4;
   
   scanf ("%1d", &num1);
   scanf ("%1d", &num2);
   scanf ("%1d", &num3);
   scanf ("%1d", &num4);
    if (num1 == 1)
{
   printf ("0\n0\n0\n0\n0", num1); 
}
   if (num2 == 1)
 {
  printf (" \n\n0\n0\n0\n0\n0", num2); 
 }
   if (num3 == 1)
{
   printf (" \n\n0\n0\n0\n0\n0", num3); 
}
   if (num4 == 1)
   {
   printf (" \n\n0\n0\n0\n0\n0", num4); 
   }

you need to use the %d in your printf to display the numbers