Thread: Need some explanation here...

This program is for "Guessing a secret number"

Code:

#include <stdio.h>
#include <stdlib.h>
int main(int argc, char *argv[])
{
char i;
printf("Guess the secret number!\n");
while(i!='8'){
i=getchar();
getchar();
printf("You've entered %c\n",i);
}
printf("You finally guessed!\n");
system("PAUSE");
return 0;
}

I understand the whole code except for 1 part.

i=getchar();
getchar(); <-why is this written again here?

Can anyone explain me that part please

thanks

I'm assuming it's to eat the newline character ('\n')

Originally Posted by itsme86

It's not the best input method since it will get confused if you input more than once character for your guess. You're better off getting the input as a string and then converting that string to an integer.

I know that but still...

I need to know why

getchar(); is written 2 times =/

See memcpy's response (post #2). What do you press after your guess to transmit it to the program? That's right, "enter" or "newline". That puts a newline character ('\n') into the input buffer. That's a total of two characters, your guess and the newline. It's a good idea to get rid of that newline before moving on. One (not very robust) way is to use another call to getchar().

Originally Posted by anduril462

See memcpy's response (post #2). What do you press after your guess to transmit it to the program? That's right, "enter" or "newline". That puts a newline character ('\n') into the input buffer. That's a total of two characters, your guess and the newline. It's a good idea to get rid of that newline before moving on. One (not very robust) way is to use another call to getchar().

Thanks a lot for explaining to me it's more clear now to me