hexadecimal and character string usage?

hello all,

Iam trying to use a character string as hexadecimal.

for example i have a char array[] = "00001767fb693bc7"

the array represents character but these are hexadecimal characters each one.

now using memcpy i want to copy to one pointer variable like below

unsing char *p;
.
.
.
memcpy(p,array,8);

but its not getting me correct result.

result should be the same like below if do .

Code:

 unsigned char mac1 = 0x00;
  unsigned char mac2 = 0x00;
  unsigned char mac3 = 0x17;
  unsigned char mac4 = 0x67;
  unsigned char mac5 = 0xfb;
  unsigned char mac6 = 0x69;
  unsigned char mac7 = 0x3b;
  unsigned char mac8 = 0xc7;
  syslog(LOG_ERR,"Changed the mac address -3 ");
  memcpy(p, &mac1, 1);
  p++;
  memcpy(p, &mac2, 1);
  p++;
  syslog(LOG_ERR,"Changed the mac address -4 ");
  memcpy(p, &mac3, 1);
  p++;
  memcpy(p, &mac4, 1);
  p++;
  memcpy(p, &mac5, 1);
  p++;
  syslog(LOG_ERR,"Changed the mac address -5 ");
  memcpy(p, &mac6, 1);
  p++;
  memcpy(p, &mac7, 1);
  p++;
  syslog(LOG_ERR,"Changed the mac address -6 ");
  memcpy(p, &mac8, 1);
  p++;*/

can any body help me here , you help would be highly appreciated.

What is actually happening?
How is memory for p allocated?

A string is rather different from the hexadecimal representation of the raw binary data.
It sounds to me like what you actually want is:

Code:

char array[] = {0x00, 0x00, 0x17, 0x67, 0xfb, 0x69, 0x3b, 0xc7};

iMalc thanks

what you said is correct,

but i have

Code:

char array[] = "00001767fb693bc7"

like this

i need to make it to like below

Code:

char array[] = {0x00, 0x00, 0x17, 0x67, 0xfb, 0x69, 0x3b, 0xc7};

how can i do using a c syntax

you help would be highly appreciated.

This is what you are looking for:
Hex String to Byte Array in C - Stack Overflow

(I googled "hex string to byte array in C" and it was the first hit)