Thread: new to c programming, Homework help

Hello everyone,

I'm new to this forum as well as c programming. I could use some guidance on a program I am trying to write. I need the program to analyze the below character and print out. I need to use if if-else or switch statements and I am lost.

• an alphabetic character (a-z or A-Z)
• a digit (0-9) or
• a special character (anything else)

Code:

#include <stdio.h>

using namespace std;

int main()

{
    char character;
    int number = 0;
    
    printf ("Please enter a character\n"); /*Asks the user to enter a character*/
    scanf("%c",&character);
    
    if (character >= 'a' && character <= 'z') {
        printf("You entered a character from a-z");
        }
           
    if (character >= 'A' && character <= 'Z') {
        printf("You entered a character from A-Z");
        }
        
    if (number >= '0' && number <= '9')
        printf("You entered a digit 0-9\n");
    
 
        else  {
        printf("You entered a special character");
        }
        
    
    fflush(stdin); 
    getchar();
    return 0;
}

If Statements in C - Cprogramming.com


FAQ > Why fflush(stdin) is wrong - Cprogramming.com

I suggest adding an space in scan format to skip spaces (linefeeds etc.).

Code:

scanf(" %c",&character);

Tim S.

Grab a sheet of paper, a pen, and go through your programm. Write down step by step exactly what will happen if your input is, say, 'b'. Don't rush through your code writing down what you believe it does; take your time to note down what it actually does in every single line.

Originally Posted by esardinha08

Hello everyone,

I'm new to this forum as well as c programming. I could use some guidance on a program I am trying to write. I need the program to analyze the below character and print out. I need to use if if-else or switch statements and I am lost.

• an alphabetic character (a-z or A-Z)
• a digit (0-9) or
• a special character (anything else)

Code:

#include <stdio.h>

using namespace std;

int main()

{
    char character;
    int number = 0;
    
    printf ("Please enter a character\n"); /*Asks the user to enter a character*/
    scanf("%c",&character);
    
    if (character >= 'a' && character <= 'z') {
        printf("You entered a character from a-z");
        }
           
    if (character >= 'A' && character <= 'Z') {
        printf("You entered a character from A-Z");
        }
        
    if (number >= '0' && number <= '9')
        printf("You entered a digit 0-9\n");
    
 
        else  {
        printf("You entered a special character");
        }
        
    
    fflush(stdin); 
    getchar();
    return 0;
}

Lose line 3 ... C does not support namespaces.

If your compiler does not give you an error, you are building a C++ program, not a C program...
And yes it does matter.

The variable "number" is not initialized. You can store digits in "char", as '0'-'9' = 0x30-0x39 in ASCII, so there's no point to have more than one type.

Also, lose the scanf and use getchar() or fgetc().

Thanks for the feedback everyone, much appreciated. The program seems to work except when I enter a numeric value such as 5, it says I entered a special character. How can I get it to say I entered a numeric value and for anything else display a special character.

Thanks all!

My final draft is:

Code:

#include <stdio.h>

int main()

{
    char character;
    
    printf ("Please enter a character\n"); /*Asks the user to enter a character*/
    scanf("%c",&character);
    
    
    if (character >= 'a' && character <= 'z') {
        printf("You entered a character from a-z");
        }
           
    else if (character >= 'A' && character <= 'Z') {
        printf("You entered a character from A-Z");
        }
        
    else if (character >= '0' && character <= '9') {
        printf("You entered a number from 0-9\n");
        }
 
    else {
        printf("You entered a special character");
         }
        
    
    fflush(stdin); 
    getchar();
    return 0;
}

And you totally ignored the link above detailing why

Code:

fflush(stdin);

is wrong.